Question

Find value of P. 2p+1, 13, 5p-3 are in AP

Answer 1

given they are in AP

t2- t1 = t3- to

13 -(2p+1)=(5p-3)-13

13-2p-1=5p- 3-13

13-1+3+13=5p+2p

28=7p

p=28/7=4

Answer 2

Answer:

Step-by-step explanation:

A=2p+1,B=13,C=5p-3

2B=A+C

2(13)=(2p+1)+(5p-3)

26=2p+5p+1-3

26=7p-2

7p=26+2

7p=28

p=28/7

p=4

a¹=2p+1=2(4)+1=8+1=9

a²=13

a³=5p-3=5(4)-3=20-3=17

A. P Is 9,13,17

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