Question

Find value of p so that quadratic equation px(x-3)+9=0 has two equal roots

Answer 1

Step-by-step explanation:

THE EQUATION IS GIVEN AS

$px(x - 3) + 9$

$p {x}^{2} - 3px + 9$

THE CONDITION FOR TWO EQUAL ROOTS IS

DISCRIMINANT=0

$( { - 3p})^{2} - 4(p)(9) = 0$

$9 {p}^{2} - 36p = 0$

$9p(p - 4) = 0$

THE VALUE OF P IS 0. AND 4