find value of p so that the quadratic equation px(x-3) + 9 has two equal roots
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two equal roots so b^2-4ac=0
equation is px^2-3px+9=0
so, [-3p^2]-4×9×p=0
9p^2=36p
p=36/9=4
equation is px^2-3px+9=0
so, [-3p^2]-4×9×p=0
9p^2=36p
p=36/9=4
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