find value of sin60 geometrically please explain in detail i will mark u as brainlist.
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heya friends ...
consider an equilateral ∆ABCwith each side equal to 2a ,
then each angle of ∆ABC is 60°
from A draw ,AD perpendicular to BC .
then clearly ,BD =DC=a
Also ,<ADB=90°
•°•<BAD =30°
from right angled triangle ∆ADB we have
AD=√AD²-AD²=√(2a)²-(a)²=√4a²-a²=√3a
now ,As we know that ...
sin¢=p/h(perpendicular/heipotenous)
so...sin60°=p/h=√3a/2a
=√3/2 .Ans.
hope it helps you.
#Rajukumar111
consider an equilateral ∆ABCwith each side equal to 2a ,
then each angle of ∆ABC is 60°
from A draw ,AD perpendicular to BC .
then clearly ,BD =DC=a
Also ,<ADB=90°
•°•<BAD =30°
from right angled triangle ∆ADB we have
AD=√AD²-AD²=√(2a)²-(a)²=√4a²-a²=√3a
now ,As we know that ...
sin¢=p/h(perpendicular/heipotenous)
so...sin60°=p/h=√3a/2a
=√3/2 .Ans.
hope it helps you.
#Rajukumar111
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