find value of t1,t2,t3
t1 - t2 + t3 = 4
t1 + t2 + 5×t3 = 20
5×t1 + t2 + t3 = 20
solve systematic
Answers
Answered by
1
firstly add (i) and (ii)
t1+3×t3=12(iv)
then subtract (ii) from (iii)
t3=2×t1
put the value in forth equation
7×t1=12
t1=12/7
t1+3×t3=12(iv)
then subtract (ii) from (iii)
t3=2×t1
put the value in forth equation
7×t1=12
t1=12/7
Similar questions