Question

find value of the x in the following expression​

Answer 1

Answer:

$a. \: \: \: given \: that \: \\ {6}^{ - x} = 36 \\ {6}^{ - x} = {6}^{2} \\ - x = 2$

$b . \: \: \: given \: that \: \\ {x}^{ - 2} = \frac{1}{25} \\ {x}^{ - 2} = \frac{1}{ {5}^{2} } \\ {x}^{ - 2} = {5}^{ - 2} \\ x = 5$

$c. \: \: given \: that \\ {3}^{ - 2x} = 81 \\ {3}^{ - 2x} = {3}^{4} \\ - 2x = 4 \\ x = \frac{4}{ - 2} \\ x = - 2$

$d .\: \: given \: that \\ \frac{1}{ {4}^{ - x} } = \frac{1}{64} \\ {4}^{x} = \frac{1}{ {4}^{3} } \\ {4}^{x} = {4}^{ - 3} \\ x = - 3$

$e .\: \: \: given \: that \\ {2}^{ - x} = \frac{1}{32} \\ {2}^{ - x} = \frac{1}{ {2}^{5} } \\ {2}^{ - x} = {2}^{ - 5} \\ - x = - 5 \\ x = 5$

Step-by-step explanation:

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