Question

find value of x : (2^-1+4^-1+6^-1+8^-1)^x = 1​

Answer 1

Answer:

X=0

Step-by-step explanation:

X=0 as we know that any number raised to the power 0 is 1 with a condition that the number should not be equal to 0.In this case that number is not 0, so it satisfies the condition for X to be 0. So X=0.