find value of x
2^(x-5) multiply by 5^(x-4) = 5
Answers
Answered by
2
2^(x -5) × 5^(x -4) = 5
take log both sides,
(x -5)log2 + (x -4)log5 = log5
(x -5)log2 = (5 - x) log5
(x -5)log2 + (x -5)log5 = 0
(x -5){log2 + log5} = 0
x = 5
take log both sides,
(x -5)log2 + (x -4)log5 = log5
(x -5)log2 = (5 - x) log5
(x -5)log2 + (x -5)log5 = 0
(x -5){log2 + log5} = 0
x = 5
Answered by
1
It's a good question but can't be solved by everyone so I m giving u a simple trick...
Attachments:
Similar questions
Computer Science,
8 months ago
Social Sciences,
8 months ago
English,
1 year ago
Hindi,
1 year ago
Science,
1 year ago