find value of x (9/7)^2x+1 × (9/7)^5 = (9/7) ^ x+2
Answers
Answered by
3
Answer:
Step-by-step explanation:
As per law of exponent
a,^m + a^n = a^(m+n,)
Hence we can write LHS as
(9/7)^2x+1+5
=(9/7^)2x+6
So the equation becomes
(9/7)^2x+6 = (9/7)^x+2
Since the base on both side us same so we can equate the powers
2x+6 = x+2
2x-x=2-6
x= -4
Answered by
1
Answer:
Step-by-step explanation:
As per law of exponent
a,^m + a^n = a^(m+n,)
Hence we can write LHS as
(9/7)^2x+1+5
=(9/7^)2x+6
So the equation becomes
(9/7)^2x+6 = (9/7)^x+2
Since the base on both side us same so we can equate the powers
2x+6 = x+2
2x-x=2-6
x= -4
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