Math, asked by yuvrajsingh6211, 5 months ago

Find value of 'x' if 1/2^1990-1/2^1991=2x​

Answers

Answered by dragan77
0

Step-by-step explanation:

(1/2)^1990-(1/2)^1991=2x

find 'x'

=(1/2)^1990-(1/2)^1990+(1/2)^1=2x

=(1/2)^1=2x

compairing

=(1/2)=x

so clearly the answer is

x=1/2

hope it helped

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