find values of K for each of the following quadratic equations so that they have two equal roots
2x* + kx + 3
Answers
Answered by
231
Hey there !
_________________
2x^2 + Kx + 3 = 0
Where,
a = 2
b = k
c = 3
[ According to ax^2 + bx + c , we just compared equation with this ]
We know, that equation has two equal roots, that means,
D = 0
We know,
D = b^2 - 4ac = 0
Keeping the values in it,
(k)^2 - 4 × 2 × 3 = 0
k^2 - 24 = 0
k^2 = 24
k = (±) √24
_________________
Hope it helps...!!!
_________________
2x^2 + Kx + 3 = 0
Where,
a = 2
b = k
c = 3
[ According to ax^2 + bx + c , we just compared equation with this ]
We know, that equation has two equal roots, that means,
D = 0
We know,
D = b^2 - 4ac = 0
Keeping the values in it,
(k)^2 - 4 × 2 × 3 = 0
k^2 - 24 = 0
k^2 = 24
k = (±) √24
_________________
Hope it helps...!!!
nick179:
l you mad
lam sorry
k=-5
ohshdogsgoshodohdohdoydgdydoydyodoydyod
can anybody tell me what is the meaning of D in this solution
discriminant
ohkk thanks got it
ni pta ap hi bta do
I am really sorry
Answered by
230
✴See the following attachment as your answer:-
The values will be:-
✔k = + 2 root 6
and ,
✔k = - 2 root 6
The values will be:-
✔k = + 2 root 6
and ,
✔k = - 2 root 6
Attachments:
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