Question

find values of x for x is not equal to 0,-4 pls pls pls pls pls pls​

Answer 1

Answer:

$x = - \frac{16}{3} \: \: \: \: or \: \: \: \: x = \frac{4}{35}$

Step-by-step explanation:

$let \: \sqrt{ \frac{x}{x + 4} } = y \\ 6y - \frac{2}{y} = 11 \\ 6 {y}^{2} - 2 = 11y \\ 6 {y}^{2} - 11y - 2 = 0 \\ 6 {y}^{2} - 12y + y - 2 = 0 \\ 6y(y - 2) + 1(y - 2) = 0 \\ (y - 2) (6y + 1) = 0 \\ therefore \: \\ y = 2 \: or \: y = - \frac{1}{6} \\ \sqrt{ \frac{x}{x + 4} } = 2 \: or \: \sqrt{ \frac{x}{x + 4} } = - \frac{1}{6} \\ \frac{x}{x + 4} = 4 \: or \: \frac{x}{x + 4} = \frac{1}{36} \\ x = 4x + 16 \: or \: 36x = x + 4 \\ - 3x = 16 \: or \: 35x = 4 \\ x = - \frac{16}{3} \: or \: x = \frac{4}{35}$