Question

Find valur of a and b of the following √3+1/√3-1=a+b√3

Answer 1

Hello Mate!

$\frac{ \sqrt{3} + 1}{ \sqrt{3} - 1} = a + b \sqrt{3} \\ \frac{ \sqrt{3} + 1}{ \sqrt{3} - 1 } \times \frac{ \sqrt{3} + 1 }{ \sqrt{3} + 1} = a + b \sqrt{3} \\ \frac{ { \sqrt{3} }^{2} + 1 + 2 \sqrt{3} }{ { \sqrt{3} }^{2} - 1} = a + b \sqrt{3} \\ \frac{4 + 2 \sqrt{3} }{2} = a + b \sqrt{3} \\ 2 + \sqrt{3 } = a + b \sqrt{3} \\ a = 2 \\ b = 1$

Hope it helps☺!✌