Question

find valve of x if number are x,2x+3,3x+6 in A.P

Answer 1

t1 = x (first term)  t2= 2x+p (Second term)  t3= 3x+6 (third term)  It is an Arithmetic Progression. The difference between two consecutice terms is constant.  t2-t1 = t3-t2  2x+p - x= 3x+6-(2x+p)  2x-x+p = 3x+6–2x-p  x+p = 3x-2x-p+6  x+p = x-p+6  p= -p+6  p+p =6  2p = 6  P = 6/2 =3  p = 3  Ans : 3  Please mark as brainliest answer

Answer 2

Topic:- Arithmetic Sequence

We know that formula of AP:- a+(n-1)d

ACCORDING TO THE QUESTION;

Let to be required terms:

T1=X

T2=2x+3

T3=3x+6

Step:-2

Define CommOn difference:-

T2-T1=T3-T2

2x+3-(x)=3x+6-(2x+3)

2x+3-x=3x+6-2x-3

x+3=3x-2x+6-3

x+3=x+3

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