Question

Find +ve integral triplets (x, y, z) such that x^y^z y^z^x z^x^y=5xyz

Answer 1

There is a 5 in RHS. So, there should be one 5 in LHS.

Let x = 5

Now, In RHS = 5×5 = 25

In power of x there should be a two also,

Therefore, y=2

Now, we get 50 in RHS

By putting z=1 in LHS,

we get 50

Therefore, x = 5

y= 2

z = 1

Hope it helps you ☺️,

Please mark me as brainlist ,

Please follow me .

Answer 2

There is a 5 in RHS. So, there should be one 5 in LHS.

Let x = 5

Now, In RHS = 5×5 = 25

In power of x there should be a two also,

Therefore, y=2

Now, we get 50 in RHS

By putting z=1 in LHS,

we get 50

Therefore, x = 5

y= 2

y= 2z = 1

Hope it helps!