find vertex, focus, directrix of parabola (X- h) ^2+4a(y- k) =0.
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Given : (x- h)² + 4a(y- k) =0
To Find : vertex, focus, directrix of parabola
Solution:
(x- h)² + 4a(y- k) =0
=> (x- h)² = - 4a(y- k)
=> (x- h)² = 4(-a)(y- k)
Vertical Parabola with vertex (h,k)
vertex = ( h , k )
focus = ( h , k - a)
Directrix y = k + a
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