Question

find volume and surface area of cube whose edge measures 3/2m ICSE
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Answer 1

Answer:

$area = s \times s \times s \\ = \frac{3}{2} \times \frac{3}{2} \times \frac{3}{2} \\ \frac{27}{8} \\ therefore \: area = \frac{27}{8} {m}^{3}$

Answer 2

Solution:

We are given that the edge of a cube is 3/2m and we have to volume and surface area of cube.

Calculating Volume

V = a³

V = (3/2)³

V = 3/2 × 3/2 × 3/2

V = 27/8

V = 3.38m³

Therefore, volume of a cube is 3.38m³.

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Calculating Surface Area

A = 6a²

A = 6 × 3/2²

A = 6 × 1.5²

A = 6 × 2.25

A = 13.5m²

Therefore, surface area of a cube is 13.5m².

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Important Formulas

CSA of cube = 4a²

TSA of cuboid = 2(lb + bh + hl)

CSA of cylinder = 2πrh

SA of sphere = 4πr²

CSA of cuboid = 2(l +b)h

CSA of cone = πrl

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