find. volume. of. rice. and. how much. canvas
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we have, r = 24/2 = 12m
and h = 3.5m
l = √(h^2 + r^2)
= √[(3.5)^2 + (12)^2]
= √(12.25 + 144)
= √156.25 = 12.5m
Volume = πr^2h/3
= (22×12×12×3.5)/7
= 1584 m^3
area if canvas required = CSA of cone
= πrl
= (22×12×12.5)/7
= 471.42 m^2
and h = 3.5m
l = √(h^2 + r^2)
= √[(3.5)^2 + (12)^2]
= √(12.25 + 144)
= √156.25 = 12.5m
Volume = πr^2h/3
= (22×12×12×3.5)/7
= 1584 m^3
area if canvas required = CSA of cone
= πrl
= (22×12×12.5)/7
= 471.42 m^2
Answered by
1
hi
its diameter is 24m
so, its radius will be 12m
volume of the rice=πr^2*h/3
=22/7*12*12*3.5/3
=528cubic meters
WKT,
l^2=r^2+h^2
=12^2+3.5^2
= 144+12.25
=166.25
cloth required to cover the heap=TSA of cone
=πr(r+l)
=22/7*12(12+166.25)
=6722.57142857
its diameter is 24m
so, its radius will be 12m
volume of the rice=πr^2*h/3
=22/7*12*12*3.5/3
=528cubic meters
WKT,
l^2=r^2+h^2
=12^2+3.5^2
= 144+12.25
=166.25
cloth required to cover the heap=TSA of cone
=πr(r+l)
=22/7*12(12+166.25)
=6722.57142857
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