Find what length of canvas 2m in width is required to make a conical tent 20m
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Hey friend nice question
Let r be the radius of tent 2 x π x r = 44 2 x 22/7 x r = 44 ∴ r = 7 m Given h = 10 m CSA of tent = π x r x l CSA of tent = π x 7 x √(72 + 102) CSA of tent = 22/7 x 7 x √(149) CSA of tent = 22 x √(149) Area of rectangle = l x b = 2 x l 2 x l = 22 x √(149) l = 11 x 12.21 l = 134.31 m Thus, the required length of canvas tent = 134.31 meters.
Hope this helps you
Let r be the radius of tent 2 x π x r = 44 2 x 22/7 x r = 44 ∴ r = 7 m Given h = 10 m CSA of tent = π x r x l CSA of tent = π x 7 x √(72 + 102) CSA of tent = 22/7 x 7 x √(149) CSA of tent = 22 x √(149) Area of rectangle = l x b = 2 x l 2 x l = 22 x √(149) l = 11 x 12.21 l = 134.31 m Thus, the required length of canvas tent = 134.31 meters.
Hope this helps you
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