Find what value of k,for which the pair of given linear equation 3x+y-5=0 and kx-2y-4=0 has unique solution
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Value of k,for which the pair of given linear equation 3x+y-5=0 and kx-2y-4=0 has unique solution
1.The given system of equations is:
kx - 2y – 4 = 0
3x + y – 5 = 0
2.The above equations are of the form
a1 x + b1 y − c1 = 0
a2 x + b2 y − c2 = 0
Here, a1 = k, b1 = -2, c1 = −4
a2 = 3, b2 = 1, c2 = -5
3. So according to the question,
For unique solution, the condition is
a1 / a2 ≠ b1 / b2
k/3 ≠ -2/1
⇒ k ≠ -6
4. Hence, the given system of equations will have unique solution for all real values of k other than -6
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