Question

Find x. 4x^2-2(a^2+b^2)x+a^2b^2=0

Answer 1

a= 4

b= -2(a2+b2)

c= a2b2

Using Discriminant formula,

D= b2-4ac

[-2(a2+b2)]2-4 x4xa2b2

4(a4+b4+2a2b2)-16a2b2

(2a2-2b2)2

 

x= (-b±D)/ 2a

x= [2(a2+b2)+2(a2-b2)]/8 = 4a2/8 = a2/2

x= [2(a2+b2)-2(a2-b2)]/8 = 4b2/8 = b2/2