if x= 1-√3 , find (x-1/x)^3
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Hi ,
x = 1 - √3 ----( 1 )
1/x = 1/ ( 1 - √3 )
= ( 1 + √3 ) / [ ( 1 - √3 )(1 + √3 ) ]
= ( 1 + √3 ) / [ 1² - ( √3 )² ]
= ( 1 + √3 ) / ( 1 - 3 )
= - ( 1 + √3 ) / 2 ---- ( 2 )
x - 1/x = 1 - √3 - [-( 1 + √3 ) / 2 ]
= 1 - √3 + ( 1 + √3 ) /2
= [ 2 - 2√3 + 1 + √3 ] /2
= ( 3 - √3 ) /2
( x - 1/x )³ = [( 3 - √3 )/2 ]³
= 1/8[ 3³ - √3³ - 3 ×3×√3( 3 - √3 )
= 1/8 [ 27 - 3√3 - 9√3(3 - √3)
= 1/8 [ 27 - 3√3 -27√3 + 27 ]
= 1/8 [ 54 - 30√3 ]
= 1/4 [ 27 - 15√3 ]
I hope this helps you.
:)
x = 1 - √3 ----( 1 )
1/x = 1/ ( 1 - √3 )
= ( 1 + √3 ) / [ ( 1 - √3 )(1 + √3 ) ]
= ( 1 + √3 ) / [ 1² - ( √3 )² ]
= ( 1 + √3 ) / ( 1 - 3 )
= - ( 1 + √3 ) / 2 ---- ( 2 )
x - 1/x = 1 - √3 - [-( 1 + √3 ) / 2 ]
= 1 - √3 + ( 1 + √3 ) /2
= [ 2 - 2√3 + 1 + √3 ] /2
= ( 3 - √3 ) /2
( x - 1/x )³ = [( 3 - √3 )/2 ]³
= 1/8[ 3³ - √3³ - 3 ×3×√3( 3 - √3 )
= 1/8 [ 27 - 3√3 - 9√3(3 - √3)
= 1/8 [ 27 - 3√3 -27√3 + 27 ]
= 1/8 [ 54 - 30√3 ]
= 1/4 [ 27 - 15√3 ]
I hope this helps you.
:)
nuha123:
thank soooo much
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