find x
6x^2-11x-2=0
................................................../
Answers
Answered by
2
6x² - 11x - 2 = 0
=> 6x² - 12 x + x - 2 = 0
=> 6x ( x - 2 ) + 1 ( x - 2 ) = 0
=> ( 6x + 1 ) ( x - 2 ) = 0
=> 6x + 1 = 0 ; x - 2 = 0
=> x = - 1 / 6 ; 2
Hence x has two values which are : ( - 1 / 6 ) and ( + 2 ).
Hope it helped !
Answered by
2
6x ^ 2 - 11 x - 2 =0
6x ^ 2 - 12 x + x - 2 = 0
Splitted middle term ..
6x ( x - 2 ) + 1 ( x - 2 ) = 0
( 6x + 1 ) ( x - 2 ) = 0
X = - 1 / 6 or 2
6x ^ 2 - 12 x + x - 2 = 0
Splitted middle term ..
6x ( x - 2 ) + 1 ( x - 2 ) = 0
( 6x + 1 ) ( x - 2 ) = 0
X = - 1 / 6 or 2
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