find x and y ??????!!!!
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Given:
(a+b) x + (a-b) y = a² + b² --- (1)
(a - b) x + ( a + b) y = a² + b² --- (2)
Multiply (1) by (a+b) and Multiply (2) by (a-b) and subtract. This eliminates the variable y. We multiply like above to make the coefficients of "y" equal in both equations.
(a+b)² x + (a² - b²) y - (a-b)² x - (a² - b²) y = (a²+b²) (a+b) - (a²+b²)(a-b)
4 a b x = 2 b (a²+b²)
x = (a²+b²)/2a
Substitute this value of x in (1) to get:
(a+b) (a²+b²)/2a + (a-b) y = a²+b²
(a-b) y = (a²+b²) * [ 2a - a - b] /2a
y = (a²+b²)/2a
Assume that a ≠ b, for canceling the factor (a-b) on both sides.
If a = b, then also x = y = (a²+b²)/2a = a = b
(a+b) x + (a-b) y = a² + b² --- (1)
(a - b) x + ( a + b) y = a² + b² --- (2)
Multiply (1) by (a+b) and Multiply (2) by (a-b) and subtract. This eliminates the variable y. We multiply like above to make the coefficients of "y" equal in both equations.
(a+b)² x + (a² - b²) y - (a-b)² x - (a² - b²) y = (a²+b²) (a+b) - (a²+b²)(a-b)
4 a b x = 2 b (a²+b²)
x = (a²+b²)/2a
Substitute this value of x in (1) to get:
(a+b) (a²+b²)/2a + (a-b) y = a²+b²
(a-b) y = (a²+b²) * [ 2a - a - b] /2a
y = (a²+b²)/2a
Assume that a ≠ b, for canceling the factor (a-b) on both sides.
If a = b, then also x = y = (a²+b²)/2a = a = b
kvnmurty:
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