find x and y in parallelogram ABCD D = 75 degree c= x b=y
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Let given quadrilateral ABCD is a parallelogram.
⇒ Then, AB∥CD and AD∥BC (Opposite sides of parallelogram are parallel)
⇒ ∠DAB = ∠BCD (Opposite angles of parallelogram are equal)
⇒ Since, it's given that ∠DAB =75
∘
. Then, ∠BCD = 75
∘
---- (1)
⇒ ∠DBC = 60
∘
---- ( 2 ) (Given)
⇒ In △DCB,
⇒ ∠BDC + ∠BCD + ∠DBC = 180
∘
⇒ ∠BDC + 75
∘
+ 60
∘
= 180
∘
[From (1) and (2) ]
⇒ ∠BDC = 180
∘
- 135
∘
∴ ∠BDC=45
∘
hope it helps you
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