Question

find x and y in the question

Answer 1

15. angle of PDA
90°+40°+D=180°
D=50°
A LINE IS 180°
ANGLE PDA+ANGLE ADC=180°
ANGLE ADC=130°
Quadrilateral opposite angle=180°
angle B+ angle ADC=180°
X+130°=180°
X=50°
Y=90°
16. AOB IS ISOLATED TRIANGLE
X=32°
so, X+32°+ANGLE AOB=180
ANGLE AOB=116°
CIRCUM RADIUS ABC
ANGLE AOB=2* ANGLE ACB
116°=2*Y
Y=58°
17.opposite angle =180°
80°+angle XOY=180°
ANGLE XOY=100°
TOTAL ANGLE 360°
X+100°=360°
X=260°
XOY IS ISOLATED TRIANGLE
Y+Y+100°=180°
Y=40°
19. ANGLE AOB
25°+ANGLE AOB+25°=180°
ANGLE AOB=130°
ANGLE AOB+ANGLE BOP=180°
130°+ANGLE BOP=180°
ANGLE BOP=50°
TANGENT B SO 90°
90°+50°+X=180°
X=40°