find x and y in this figure
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/_ b=90°/2=45*
/_ c= 45
because bd=y
cd=/_b
side same of same triangle have same angle
/_A=45
because bd = x
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Answer:
∠ x = 52° and ∠y = 48°
Step-by-step explanation:
In the figure ∠y = ∠DBC [as DC = DB ] ___________(i)
∠BDC + ∠BDA = 180° [linear pair]
∠BDC + 96° = 180°
⇒ ∠BDC = 84° ____________(ii)
In ΔBCD ,
∠y + ∠DBC + ∠BDC = 180° [angle sum property of Δ]
∠y + ∠y + 84° = 180° [from (i) and (ii)]
⇒ 2∠y = 180° - 84°
⇒ ∠y = ⇒ ∠y = 48°
NOW, ∠DBC + ∠DBA = 90° [Given 90° ]
48° + ∠DBA = 42°
Now, In ΔABD,
∠x + ∠ABD + ∠DBA = 180° [angle sum property of Δ]
∠x + 42° + 96° = 180°
⇒ ∠x = 180° - 138°
⇒ ∠ x = 52°
please mark my answer the brainliest .
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