find x and y inthe figure
chapter me triangle congruency. value of x and y
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Answered by
1
According to the figure,
BD = CD
So, angle CBD = Angle BCD [ Angles opposite to equal sides are equal ]
Angle CBD = 55 °
Angle B = 38 ° + 55 ° = 93 °
In triangle BAD,
Angle BAD + Angle B + Angle BDA = 180°
55° + 93 ° + y ° = 180 °
y ° = 180 ° - 148 °
y ° = 32 °
Similarly, in Triangle, BOD,
Angle DBC + x° + y ° = 180 °
55 ° + x° + 32 ° = 180 °
x ° = 180 ° - 87 °
x ° = 93 °
BD = CD
So, angle CBD = Angle BCD [ Angles opposite to equal sides are equal ]
Angle CBD = 55 °
Angle B = 38 ° + 55 ° = 93 °
In triangle BAD,
Angle BAD + Angle B + Angle BDA = 180°
55° + 93 ° + y ° = 180 °
y ° = 180 ° - 148 °
y ° = 32 °
Similarly, in Triangle, BOD,
Angle DBC + x° + y ° = 180 °
55 ° + x° + 32 ° = 180 °
x ° = 180 ° - 87 °
x ° = 93 °
Answered by
0
hey frnd....
in the given figure....
in ∆
<BOD = <ABO + <BAO ( sum of interior angles is equal to opposite outer angle)
x = 38+55
x = 93°
now in ∆ DBC
<DBC = <DCB
<DBC = 55°
now in ∆ DBO
<BDO + <DBO <DOB = 180°
y = 180- (55+93)
y = 180-148
y = 32°
so the value of
x = 93°
y = 32°
HOPE THIS HELP YOU ☺☺❤❤❤❤
in the given figure....
in ∆
<BOD = <ABO + <BAO ( sum of interior angles is equal to opposite outer angle)
x = 38+55
x = 93°
now in ∆ DBC
<DBC = <DCB
<DBC = 55°
now in ∆ DBO
<BDO + <DBO <DOB = 180°
y = 180- (55+93)
y = 180-148
y = 32°
so the value of
x = 93°
y = 32°
HOPE THIS HELP YOU ☺☺❤❤❤❤
Anonymous:
thanks
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