Question

find x cube + y cube +24 xy, when x+y=8​

Answer 1

here's your

Answer:

Given:

${x}^{3} + {y}^{3} + 24$

solution:

$(x + y)( {x}^{2} - xy + {y}^{2} ) + 24 \\ = 8 + ( {x}^{2} - 2xy + {y}^{2} + xy) \\ = 8 + (x + y)^{2} + xy \\ = 8 + 8 ^{2} + xy \\ 8 + 64 + xy \\ 72 + xy$

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