Question

Find x here....

Plz someone answer this !!!

Answer 1

( 2x-10) °+(3x+20) °=180°
5x°+10°=180°
5x°=180°-10°
5x°=170°
x°=170°/5=34°
Now putting the value of x
Angle AOC = ( 2x-10)°=(2*34-10)°=(68-10)°=58°
Angle BOC = (3x+20)°=(3*34+20)°=(102+20)°
=122°

Answer 2

∠aoc+∠boc=180°(straight line property)
(2x-10)°+(3x+20)°=180°
5x-10°=180° 
5x=190°
x=38°
 <aoc= ( 2x-10)°=(2*34-10)°=(68-10)°=58° and ∠boc =(3x+20)°=(3*34+20)°=(102+20)°
=122°