Find , 'x' if:
(-1/2)power5×(-1/2)power6=(-2)
power x
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hey buddy here is ur answer
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(-1/2)^5×(-1/2)^6=-2^x
(-1/2)^5+6=-2^x. [(a/b)^m×(a/b)^n=(a/b)^m+n]
(-1/2)^11=-2^x
-2^-11=-2^x. [(b/a)^m=(a/b)^-m)
as bases are same,by equating
X=-11.
(-1/2)^5+6=-2^x. [(a/b)^m×(a/b)^n=(a/b)^m+n]
(-1/2)^11=-2^x
-2^-11=-2^x. [(b/a)^m=(a/b)^-m)
as bases are same,by equating
X=-11.
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