Question

find x if 16 x2 ²x+¹ =128​

Answer 1

Answer:

HEY THERE !!

HERE IS YOUR ANSWER ...

Step-by-step explanation:

16 ×2² × x +¹ = 128

16× 4 × x =128

64 x= 128

x = 128÷64

x = 2

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Answer 2

Answer:

x

4

−

2

x

3

+

8

x

2

−

32

x

−

128

=

0

Factor the left side of the equation.

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(

x

−

4

)

(

x

+

2

)

(

x

2

+

16

)

=

0

If any individual factor on the left side of the equation is equal to

0

, the entire expression will be equal to

0

.

x

−

4

=

0

x

+

2

=

0

x

2

+

16

=

0

Set the first factor equal to

0

and solve.

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x

=

4

Set the next factor equal to

0

and solve.

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x

=

−

2

Set the next factor equal to

0

and solve.

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x

=

4

i

,

−

4

i

The final solution is all the values that make

(

x

−

4

)

(

x

+

2

)

(

x

2

+

16

)

=

0

true.

x

=

4

,

−

2

,

4

i

,

−

4

i