find x if 4(sec²59-cot²31)/3-⅔ sin90+3tan²56×tan²34=x/3
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Given,
4(sec2 59°-cot231)/3-2/3 Sin 90°+tan256xtan234 = (x/3)
(x/3) = 4[sec2 (90° – 31°) - cot231)/3] - 2/3 (1) + tan2(90° – 34°) x tan234
(x/3) = 4[cosec2 31° - cot231°)/3] - 2/3 + cot2 34° x tan234
(x/3) = 4[1]/3 - 2/3 + 1
(x/3) = 4/3 - 2/3 + 1
(x/3) = 2/3 + 1 = 5/3
Hence x = 5
4(sec2 59°-cot231)/3-2/3 Sin 90°+tan256xtan234 = (x/3)
(x/3) = 4[sec2 (90° – 31°) - cot231)/3] - 2/3 (1) + tan2(90° – 34°) x tan234
(x/3) = 4[cosec2 31° - cot231°)/3] - 2/3 + cot2 34° x tan234
(x/3) = 4[1]/3 - 2/3 + 1
(x/3) = 4/3 - 2/3 + 1
(x/3) = 2/3 + 1 = 5/3
Hence x = 5
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