Question

find x if (√6)^x-2 = 1​

Answer 1

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$(\sqrt{6})^{x-2}=1$

$⇒\sqrt{6}^{x-2}=1$   ---- (i)

We know,

√6⁰=1

So, Let's substitute (√6⁰=1) in (i).

$⇒\sqrt{6}^{x-2}=\sqrt{6}^{0}$

As bases are the same let's cancel the bases.

So,

⇒x-2=0

⇒x=2

$\huge\boxed{x=2}$

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