Question

find x if
(7/5)^2x+1 *(7/5)^5= (7/5)^x+2​

Answer 1

Answer:

Step-by-step explanation:

solution

(7/5)^2x+1 * (7x/5)=(7/5)^x+2

= (7^2x+1+5)/5 =(7/5)^x+2

cross multiply

35x^2x+1 =35x^x+2

cancel the index, you will be left with

2x+1=x+2

now collect like terms

2x-x=2-1

=x=1