find x, if 9*3^x=(27)^2x-3
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Answer:
x = 11/5
Step-by-step explanation:
=> 9×3^x = (27) ^(2x -3)
=> 3×3^x = ( 3) ^3(2x-3)
=> 3^2 × 3^x = ( 3 ) ^(6x-9)
mᵃ * mᵇ = mᵃ⁺ᵇ
=> 3^(2+x)= 3^(6x-9)
if mⁿ = mˣ, then n = x
therefor, 2+x = 6x-9
x-6x = -9-2
-5x = -11
x = 11/5
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