Find x, if 9 x 3^x = (27)^2x-5
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Answer:
17/5
Step-by-step explanation:
9×3∧x can be expressed as 3∧2×3∧x = 3∧(2+x)
(27)∧2x-5 can be expressed as 3∧3(2x-5) = 3∧6x-15
equating both sides we get
3∧(x+2) = 3∧(6x-15)
when bases are equal then must also be equal to have whole equal
∴ x+2 = 6x-15
⇒ 5x=17
x=17/5
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