Question

find X if log^x3√5 =6​

Answer 1

Answer:

x=25

Step-by-step explanation:

$log_{ \sqrt[3]{5} }(x) = 6$

$3 log_{5}(x) = 6$

$log_{5}( {x}^{3} ) = 6$

${x}^{3} = {5}^{6}$

$x = {5}^{2}$

$x = 25$

Answer 2

Answer:

$\bold\red{x=25}$

Step-by-step explanation:

It is being given that, a logarithmic equation,

$log_{ \sqrt[3]{5} }(x) = 6$

But, we know that, if

$log_{a}(b) = m$

then, according to properties of logarithm,

$= > b = {a}^{m}$

So, according to this property, we get

$= > x = { (\sqrt[3]{5}) }^{6}$

or, we can simplify,

$= > x = { ({5}^{ \frac{1}{3} }) }^{6}$

further simplifying, we get

$= > x = {5}^{ \frac{6}{3} }$

$= > x = {5}^{2}$

$= > x = 25$

Hence, x = 25