find 'x' if point Q ( 0, 1) is equidistant from the point p(5,-3) and R (x,6)
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Answer:
the value of x is 4
Step-by-step explanation:
distance formula is √(x1²-x2² )+(y1² - y2²)
applying distance formula and find distance PQ and RQ
according to question, PQ= RQ
SO, (PQ)²= (RQ)². ( to remove square root)
on solving you will get x=4
I hope this helps you if you still have any confusion then please feel free to ask.
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