Question

Find x if root3 tan 2x=cos60+sin45.cos45

Answer 1

sorry the answer s wrong.. from 5th step.. after 4th step
tan2x=1/root3
tan30=1/root3
tan2x=tan30
2x=30
x=15

Answer 2

Heya,

$\sqrt{3} \tan(2x) = \cos(60°) + \sin(45°) \cos(45°)$

$\sqrt{3} \tan(2x) = 1 \div 2 + 1 \div \sqrt{2} \times 1 \div \sqrt{2}$

$\sqrt{3} \tan(2x) = 1 \div 2 + 1 \div 2$

$\sqrt{3} \tan(2x) = 1$

$\tan(2x) = 1 \div \sqrt{3}$

$\tan(2x) = 1 \div \sqrt{3} = \tan(30°)$

$2x = 30°$

$x = 15°$

Value of x is 15°

Hope this helps you.....:)