Math, asked by nehalsreekumar, 8 days ago

find x in (3/4)^x-3 = (4/3)^x-1

Answers

Answered by riturajbhaskar13
1

Answer:

(3/4)^x-3 = (4/3)^x-1

(3/4)^x-3 = (3/4)^-(x-1). [reciprocal]

(3/4)^x-3 = (3/4)^-x+1

x-3 = -x +1

x+x = 1+3

2x = 4

x = 2

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