Math, asked by abhiabhi626, 1 year ago

find x in log 2x+log3x+log6x=11

Answers

Answered by Kiran1089

1

log2x[3x][6x]=ll

loga+logb+logc=log abc

log36xcube=11

3 log36 x=11

3 logx6 Sq=11

6log6x=11

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