Question

FIND X in maths find the answer ​

Answer 1

Answer:

this is the ans.of your question

hope it helps

Answer 2

★ How to do :-

Here, we are given with the measurement of the angles of two exterior angles and in the interior of that triangle we are given with an angle with a variable 'x'. We are asked to find the value of that angle 'x' in this question. So, first we should find the value of other two angles in the interior of triangle except the angle 'x' i.e, in the attachment it's mentioned as ∠1 and ∠2, which should be found using the exterior angles. Later, we can find the value of 'x' using the concept given while solving. So, let's solve!!

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➤ Solution :-

First, find the value of ∠1 by using the concept of linear pair of angles.

Value of ∠1 :-

${\tt \leadsto \angle{1} + {105}^{\circ} = {180}^{\circ}}$

Remove the degree symbol which makes easier to understand.

${\tt \leadsto \angle{1} + 105 = 180}$

Shift the number 105 from LHS to RHS, changing it's sign.

${\tt \leadsto \angle{1} = 180 - 105}$

Subtract to get the value of ∠1.

${\tt \leadsto \underline{\angle{1} = {75}^{\circ}}}$

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Now, find the value of ∠2 by the same process.

Value of ∠2 :-

${\tt \leadsto \angle{2} + {120}^{\circ} = {180}^{\circ}}$

Remove the degree symbol which makes easier to understand.

${\tt \leadsto \angle{2} + 120 = 180}$

Shift the number 120 from LHS to RHS, changing it's sign.

${\tt \leadsto \angle{2} = 180 - 120}$

Subtract to get the value of ∠2.

${\tt \leadsto \underline{\angle{2} = {60}^{\circ}}}$

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Now, find the value of 'x' by using the concept that all the angles in a triangle always measures 180°.

Value of 'x' :-

${\tt \leadsto \angle{1} + \angle{2} + x = {180}^{\circ}}$

Substitute the values.

${\tt {75}^{\circ} + {60}^{\circ} + x = {180}^{\circ}}$

Remove the degree symbol which makes easier to understand.

${\tt \leadsto 75 + 60 + x = 180}$

Add the numbers given in LHS.

${\tt \leadsto 135 + x = 180}$

Shift the number 135 from LHS to RHS, changing it's sign.

${\tt \leadsto x = 180 - 135}$

Subtract to get the value of 'x'.

${\tt \leadsto \pink{\underline{\boxed{\tt x = {45}^{\circ}}}}}$

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Hence solved !!