find x in the following figure
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s=90°
q=90°
x=360°-(60°+70°+90°+90°)
x=360°-310°
x=50°
q=90°
x=360°-(60°+70°+90°+90°)
x=360°-310°
x=50°
manvigirly2022:
pls tell me the formula how
Answered by
4
Answer:
Step-by-step explanation:
60°+<SRQ =180° ( linear pair )
<SRQ =180°-60°
<SRQ=120°
Similarly,
<TSR=90°,
<PTS=110°
And
We know that
Angle sum property of pentagon=540°
So,
<SRQ+<TSR+<PTS+<QPT+<RQP=540°
120°+90°+110°+<QPT+90°=540°
410°+<QPT=540°
<QPT=540°-410°
<QPT=130°
And ,<QPT+<x°=180(linear pair)
130°+ x°=180
x°=180-130
x°=50
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