Question

It is known that a box of 600 electric bulb contain 12 defective bulbs . One bulb is taken out at random from this box . What is the probability that is a non defective bulb ?

Answer 1

Answer:49/50

Step-by-step explanation:

Non defective bulb = 600-12=588

Probability=588/600=49/50.

Hope it will help uhh.....

Answer 2

Total Bulbs=600
Defective Bulbs=12
Good Bulbs=600-12=588
P(Non Defective Bulb)=588/600=49/50