find x in the following figures please give true answer i will mark u Brainliest and give 5 thanks to you
Answers
Answer:
value of x in the first figure: C
Step-by-step explanation:
angle ABC =180°- ABE(LINEAR PAIR)
=180°-120°
= 60°
Angle ACB=180-110(LINEAR PAIR)
=70°
70°+60°+x=180°(angle sum property of a triangle )
x=180-130
x=50
Value of x in figure d:
35+45+50+D=360(angle sum property of quadilateral)
D=360-130
D=230
230+x=360
x=360 - 230
x= 130
VALUE OF X IN FIGURE E
60+45+ACB=180⁰(angle sum property of triangle)
ACB = 180- 105
ACB= 75=DCE(vertical opposite angle)
80+x+75=180
x=180-155
x=25
VALUE OF X IN FIGURE F:
(3x+40)+4x=11x-60 (sum of opposite interior angle is equal
to the exterior angle)
3x+40+4x=11x-60
11x-7x=60+40
4x=100
x=100÷4
x=25
VALUE OF X IN FIGURE G:
100+a=180(linear pair)
a=80
80+3x=7x
4x=80
x= 80÷4
=20
VALUE OF X IN FIGURE H:
90+a = 180(linear pair )
a= 180-90
a=90
90+30+b=180(angle sum property of triangle)
b=180-120
b= 60 = c (vertical opposite angle)
48+60+x=180(angle sum property of triangle)
x= 180-108
x=72
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