Question

Find x in the given Angle ABC , where AC = BC and Angle ACD = 130 degree​

Answer 1

Step-by-step explanation:

A straight line makes 180° angle.

such that,

angle ACB + angle ACD = 180°

=> angle ACB + 130° = 180°

=> angle ACB = 180° -130° = 50°.

Now triangle CAB is an isosceles triangle because AC = BC.

So by isosceles triangle property, angles corresponding to equal sides are also equal.

i.e., angle CAB = angle CBA

Now, Sum of all angles of a triangle is 180°

x + x + 50° = 180°

=> 2x = 180° - 50° = 130°

=> x = 65°

Answer 2

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