Question

find x in x^2/4 + 2x +15​

Answer 1

Answer:

No real roots

Step-by-step explanation:

Given,

$\frac{x^2}{4} + 2x + 15$

To Find:-

Value of 'x'

Let's Understand:-

To Find the value of 'x' we need to equate the expression to zero and we will get the value of x by splliting into middle term or by using quadratic formula.

Solution:-

$\frac{x^2}{4} + 2x + 15 = 0$

Taking L.C.M as 4 :-

$\frac{x^2 + 2x(4) + 15(4)}{4} = 0$

$\frac{x^2 + 8x + 60}{4} = 0$

Transposing 4 to R.H.S :-

$x^2 + 8x + 60 = 0\times 4$

$x^2 + 8x + 60 = 0$

Comparing with ax^2 + bx + c = 0

we can say,

a = 1

b = 8

c = 60

Quadratic formula :-

$\dfrac{-b\pm\sqrt{b^2 - 4ac}}{2a}$

Substituting values :-

$\dfrac{- 8\pm\sqrt{(8)^2 - 4(1)(60)}}{2(1)}$

$\frac{8\pm\sqrt{64 - 240}}{2}$

$\frac{-8\pm\sqrt{-176}}{2}$Hence, as b^2 - 4ac is negative :-

there are no real values for 'x'.

Since, no real roots for" x^2/4 + 2x +15​".