find x in { ( x - b - c )/ a } + {( x-c-a)/ b} + { ( x - a - b ) / c } = 3
please give full solution . I will mark you brainliest . For your confirmation the ans. is (a + b + c )
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Rishikumarcsk:
why in the world have you reported me sunil205. I helped you and you reported me
go die b
go die b*tch
sorry friend but believe the options of marking as brainliest is not here and i do not know how it will
then why did you report me
don't worry i promise i will mark you brainliest when the option appears and if i do not do so then you can abuse me
please tell me what happen by reporting answers.
they warn my account that they will ban me bro
sorry for doing so unwillingly.
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(x - b - c)/a + (x - a - b)/c + (x - c - a) / b = 3
bc(x - b - c) + ab(x - a - b) + ac(x - c - a) = 3abc
bcx - b²c - bc² + abx - a²b - ab² + acx - a²c - ac² = 3abc
abx + bcx + cax = 3abc + a²b + ab² + b²c + bc² + a²c + ac²
x(ab + bc + ac) = abc + a²b + ab²+ abc + b²c + bc²+ abc + a²c + ac²
x(ab + bc + ac) = ab(c + a + b) + bc(a + b + c) + ac(b + a + c)
x(ab + bc + ac) = (a + b + c)(ab + bc + ac)
x = (a + b + c)(ab + bc + ac)/(ab + bc + ac)
x = a + b + c
bc(x - b - c) + ab(x - a - b) + ac(x - c - a) = 3abc
bcx - b²c - bc² + abx - a²b - ab² + acx - a²c - ac² = 3abc
abx + bcx + cax = 3abc + a²b + ab² + b²c + bc² + a²c + ac²
x(ab + bc + ac) = abc + a²b + ab²+ abc + b²c + bc²+ abc + a²c + ac²
x(ab + bc + ac) = ab(c + a + b) + bc(a + b + c) + ac(b + a + c)
x(ab + bc + ac) = (a + b + c)(ab + bc + ac)
x = (a + b + c)(ab + bc + ac)/(ab + bc + ac)
x = a + b + c
pleasemark me the brainliest
ok but the option of marking you brainliest is disappear
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