Math, asked by nandhini2794, 1 month ago

find x in x²-3x+2=0

Answers

Answered by iitjeetopper1

0

Answer:

(x-2) (x-1) so

x can be 2 or 1

Answered by sanmaykamble20062008

1

Answer:

$given \: {x}^{2} - 3x + 2 = 0 \\ = {x}^{2} - 2x - 1x + 2 = 0 \\ (resolving \: the \: expression \: ) \\ x(x - 2) - 1(x - 2) = 0 \\ (taking \: common \: factors \: ) \\ (x - 2)(x - 1) = 0 \\ (taking \: common \: factors \: ) \\ therefore \: \\ x - 2 = 0 \: or \: x - 1 = 0 \\ (equating \: each \: factor \: of \: zero \: ) \\ therefore \: \\ x = 2 \: or \: x + 1 \\ therefore \\ 2 \: and \: 1 \: are \: roots \: of \: {x}^{2} - 3x + 2 = 0$

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